Nilai dari integral (4cos2x – 3sin3x) batas atas π/2 batas bawah π/3 dx = ...
Pembahasan:
π/3∫π/2 (4 cos 2x – 3 sin 3x) dx = ...
= |4 sin 2x – (– 3 cos 3x)|π/2
|2 3 |π/3
= |2 sin 2x + cos 3x|π/2
π/3
= (2 sin π + cos 3π) – (2 sin 2π + cos π)
2 3
= (0 + 0) – (2.√3 _ 1)
2
= 1 – √3