Diketahui rumus fungsi f(x – 2) = 4x – 3.
Nilai f(–1) adalah
1
Pembahasan:
Cara 1:
f(x – 2) = 4x – 3
= 4(x – 2) – 3 + 8
= 4(x – 2) + 5
f(x) = 4x + 5
f(–1) = 4 × (–1) + 5
= –4 + 5
= 1
Cara 2:
f(x – 2) = 4x – 3
f(–1) = . . . .
x – 2 = –1
x = –1 + 2
x = 1
⇔ f(–1) = f(1 – 2) = 4 × 1 – 3 = 4 – 3 = 1