Jika ₋₂∫¹ (2x + n) dx = 9,

nilai n =

6

Pembahasan:

₋₂∫¹ (2x + n) dx = 9

₋₂∫¹ (2x + n) dx = 9

[½·2x² + n]¹₋₂ = 9

[x² + n]¹₋₂ = 9

[1² + n] – [-2² + n] = 9

1 + n – 4 + n = 9

–3 + 2n = 9

2n = 9 + 3

n = 12

        2

   = 6

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