Jika 6(3⁴⁰)(²log log a) + 3⁴¹(²log log a)

maka nilai a adalah

8

Pembahasan:

6(3⁴⁰)(log₂ a) + 3⁴¹ (log₂ a) = 3⁴³

3⁴¹ . [2 . log₂ a + log₂ a] = 3⁴³

3⁴¹ . [3 . log₂ log₂] = 3⁴³

log² a = 3

a = 2³ = 8

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