Larutan jenuh L(OH)₃ mempunyai pH = 10, maka harga Ksp L(OH)₃
adalah ...
L(OH)₃ ⇆ L³⁺ + 3OH⁻
Ksp L(OH)₃ = [L³⁺] [OH⁻]³
Jika pH = 10
maka pOH = 14 - 10 = 4
[OH⁻] = 10⁻⁴
L(OH)₃ ⇆ L³⁺ + 3OH⁻
3,3.10⁻⁵ 10⁻⁴
Ksp L(OH)₃ = [L³⁺] [OH⁻]³
= (3,3.10⁻⁵)(10⁻⁴)³
= 3,3.10⁻¹⁷