Limit x mendekati 3 x² – x – 6/4 – √5x+1 =
Penyelesaian:
Dengan mengalikan sekawannya, maka
lim x² – x – 6 ₓ 4 + √5x+1
x￫3 4 – √5x+1 4 – √5x+1
= lim (x² – x – 6)(4 + √5x+1)
x￫3 16 – (5x+1)
= lim (x–3)(x + 2)(4 + √5x+1)
x￫3 – (5x – 15)
= lim (x–3)(x + 2)(4 + √5x+1)
x￫3 –5(x – 3)
= lim (x + 2)(4 + √5x+1)
x￫3 –5
= (3 + 2)(4 + √5.3+1)
–5
= 5(4 + 4)
–5
= –8