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Integral 2/x√x batas atas 2 batas bawah 1 dx =

Pembahasan:
₁∫⁴   2   dx = ₁∫⁴ 2x⁻³'² dx
      x√x
= | 2  x⁻¹'²|⁴₁
     -½
= |–4x⁻¹'²|⁴₁
= |–4|⁴₁
     √x
= (–4 ) _ (–4)
     √4       √1
= – 2 + 4
= 2